CBSE Class 10 · Maths · 2026-27

Coordinate Geometry CBQs — CBSE Class 10 (2027) with step-wise solutions

Real competency-based questions on Coordinate Geometry. Try each one on paper first, then open the solution to see how the marks are earned, step by step.

Sample Coordinate Geometry CBQs

  1. Question 1MCQ1 mark
    On a scorer's chart of a cricket ground, the stumps at the bowler's end are at O(0, 0) and every unit is 1 m. A fielder picks up the ball at F(-18, 24) and throws it straight at these stumps. How far does the ball travel to reach the stumps?
    • 30 m
    • 42 m
    • 6 m
    • √252 m
    Show step-wise solution
    1. [1 mark] OF = √[(-18 - 0)² + (24 - 0)²] = √(324 + 576) = √900 = 30 m.

    Answer: 30 m

  2. Question 2MCQ1 mark
    On a city map (1 unit = 1 km) the railway station is at R(-4, 7) and the bus depot is at B(10, -3). The city plans a metro station exactly halfway between them on the straight road joining R and B. At which point should the metro station be built?
    • (7, -5)
    • (3, 2)
    • (6, 4)
    • (14, -10)
    Show step-wise solution
    1. [1 mark] Midpoint of RB = ((-4 + 10)/2, (7 + (-3))/2) = (6/2, 4/2) = (3, 2).

    Answer: (3, 2)

  3. Question 3Assertion-Reason1 mark
    On a district map (1 unit = 1 km) a post office is at P(-2, 3) and a police station is at Q(4, -5). Assertion (A): The straight-line distance between the post office and the police station is 8 km. Reason (R): The distance between the points (x₁, y₁) and (x₂, y₂) is √[(x₂ - x₁)² + (y₂ - y₁)²].
    • (A) Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
    • (B) Both Assertion and Reason are true but Reason is NOT the correct explanation of Assertion.
    • (C) Assertion is true but Reason is false.
    • (D) Assertion is false but Reason is true.
    Show step-wise solution
    1. [1 mark] (D): PQ = √[(4 + 2)² + (-5 - 3)²] = √(36 + 64) = √100 = 10 km, not 8 km, so A is false; R is the correct distance formula, so R is true.

    Answer: (D)

  4. Question 4Short answer2 marks
    A drone delivery company plots its locations on a city grid in which 1 unit = 1 km. Its warehouse is at W(2, 3) and a customer's house is at H(10, 9). The drone flies along the straight line from W to H. Find the distance the drone flies.
    Show step-wise solution
    1. [1 mark] WH = √[(10 − 2)² + (9 − 3)²] = √(8² + 6²) = √(64 + 36).
    2. [1 mark] WH = √100 = 10 units, so the drone flies 10 km.

    Answer: 10 km

  5. Question 5Case study4 marks
    For the annual day, the stage of a school auditorium is marked as a coordinate grid with 1 unit = 1 m. A straight lighting bar runs from bracket L1(−4, 6) to bracket L2(8, 0). The lead singer stands at S(3, 0). Based on the above information, answer the following questions: (i) Find the coordinates of the mid-point M of the lighting bar. (ii) A spotlight P is clamped on the bar so that it divides L1L2 in the ratio 1 : 2. Find the coordinates of P. (iii) Find the distance of the singer from P and from M, and state which of the two is nearer to her.
    Show step-wise solution
    1. [1 mark] (i) M = ((−4 + 8)/2, (6 + 0)/2) = (2, 3).
    2. [1 mark] (ii) P = ((1 × 8 + 2 × (−4))/3, (1 × 0 + 2 × 6)/3) = (0/3, 12/3) = (0, 4).
    3. [1 mark] (iii) SP = √((3 − 0)² + (0 − 4)²) = √(9 + 16) = 5 m; SM = √((3 − 2)² + (0 − 3)²) = √(1 + 9) = √10 m.
    4. [1 mark] (iii) Since 10 < 25, √10 < 5, so M is nearer to the singer, at √10 m (SP = 5 m).

    Answer: (i) M(2, 3) (ii) P(0, 4) (iii) SP = 5 m, SM = √10 m; M is nearer

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